Horizontal component = ( F \times \sin \phi )? Let’s be careful: The normal force is perpendicular to the inclined face. The horizontal component of that normal force is ( F \cos(\textangle from vertical) ) or ( F \sin(\textangle from horizontal) ). Better: Angle of face from vertical = ( \phi = \arctan(1/4) = 14.04^\circ ). So horizontal component ( F_h = F \sin \phi )? Wait – if force is normal to face, and face is tilted away from vertical by ( \phi ), then the normal vector is horizontal component = ( F \sin \phi ) and vertical component = ( F \cos \phi ). Check: If face were vertical (( \phi=0 )), horizontal = F, vertical = 0 – correct. If face horizontal (( \phi=90^\circ )), horizontal = 0, vertical = F – correct.

: Determining the magnitude and location (Center of Pressure) of water pressure acting on the dam face.

: Evaluating the Factor of Safety (FS) against sliding and overturning.